Posted by **Jon** on Wednesday, April 9, 2008 at 9:10pm.

I need to find the future population using the model P=42+20ln(11t+1)

t= time in years

I need to find when it will be 180. I have my work below, but I am stuck. The answer I get is not right, it will not add up to 180. Maybe I am wrong some where.

P=42+20ln(11t+1)

180=42+20ln(11t+1)

-42 -42

(138/20)=(201n(11t+1)/20)

6.9=1n(11t+1)

e(6.9)=e^ln(11t+1)

e(6.9)=11t+1

-1 -1

[e(6.9)-1/11]=(11t/11)

t=[e(6.9)-1/11]

my wrong answer: 1.614193818

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