Algebra
posted by Jon on .
I need to find the future population using the model P=42+20ln(11t+1)
t= time in years
I need to find when it will be 180. I have my work below, but I am stuck. The answer I get is not right, it will not add up to 180. Maybe I am wrong some where.
P=42+20ln(11t+1)
180=42+20ln(11t+1)
42 42
(138/20)=(201n(11t+1)/20)
6.9=1n(11t+1)
e(6.9)=e^ln(11t+1)
e(6.9)=11t+1
1 1
[e(6.9)1/11]=(11t/11)
t=[e(6.9)1/11]
my wrong answer: 1.614193818

When you divide by 11, don't you need to divide e^6.9 by 11 also?