A 2.00 resistor, and a 12.0 resistor are connected in parallel across a 20.0-V battery. What is the current flowing through the 2.00 resistor?
This is all I understand. Can you explain step by step and show how to get the answer?
To find current, C = vsource/R
C = 20.0/2.00 they're only asking for the current in the 2.00 resistor, not the whole thing. I REALLY don't understand where ohm's are comming into the picture, maybe they have something to do with it but the question still asks "what is the current for the 2.00 resistor" and either way you do the math, the only answer you get is 10.0
Physics repost - bobpursley, Wednesday, April 9, 2008 at 8:14pm
Arrrgggg. Where did I read a ten ohm resistor was added in series. You are right. Sorry.