Posted by Kate on Wednesday, April 9, 2008 at 4:01pm.
Stoichiometry. All of these are stoichiometry.
a). Look at the equation. The equation TELLS you that 1 mole of Fe2O3 reacts with 3 mols CO (notice that's CO and not Co) to produce 2 mols Fe and 3 mols CO. Therefore, for A, you KNOW from the equation that 3 mols CO will produce 3 mols CO2, so how much CO2 can we get from 75 mols CO?
b. same type problem a a.
c. Convert 454 g Fe2O3 to mols. mols = grams/molar mass. Convert mols Fe2O3 to mols CO2. Then convert mols CO2 to grams CO2.
d. same kind of problem as c.
e. another problem within this one but the same type as c or d.
Post your work if you get stuck.
Your original equation is not balanced. It should be
2 Fe2O3 + 3 Co = 2 Fe + 3 CO2
a) The Fe:Co mole ratio is 2:3
Use that fact to do the calculation
b) The CO2:Fe2O3 mole ratio is 3:2
c) Convert 454 g of Fe2O3 to moles. You will produce 1.5 times as many moles of CO2. Convert that number of moles to grams
d) The CO:Fe2O3 molar ratio is 3:2
e) The CO2:CO molar ratio is 1:1. Use that to get the mass ratio
Someone will be glad to critique your work.
Ignore my answer and go with DrBob's I did not notice that Co should have been CO
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