Homework Help: Math (Trigonometry)

Posted by mtd on Wednesday, April 9, 2008 at 1:37pm.

square root(a^2 -u^2) where a>0, let u=(a sinx) where -pi/2<x<pi/2

answer is (a cosx) and I don't know how to get there

Math (Trigonometry) - Reiny, Wednesday, April 9, 2008 at 1:59pm
√(a^2 -u^2) where u = asinx
= √(a$ - a^2(sinx)^2)
= √(a^2(1 - (sinx)^2)
= a√(cosx)^2
= a cos x

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