Posted by **Dennis** on Wednesday, April 9, 2008 at 10:36am.

Solve in terms of sine and cosine:

sec(x) csc(x)- sec(x) sin(x)

so far I have:

1/cos(x) 1/sin(x) - 1/cos(x) sin(x)

I am not sure where to go to from there. The book says the answer is cot(x) or cos(x)/sin(x)

Thank you in advance.

- Trig -
**drwls**, Wednesday, April 9, 2008 at 10:49am
sec(x) csc(x)- sec(x) sin(x)

= (1/cos x)(1/sinx) - sinx/cosx

= [(1/sinx)-sinx]/cos x

= [1 - sin^2x]/(sin x cos x)

= cos^2 x/(sin x cos x)

= cosx/sinx = cot x

- Trig -
**Dennis**, Wednesday, April 9, 2008 at 11:03am
Dang, I see where I messed up. Thank you so much.

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