Homework Help: Trig

Posted by Dennis on Wednesday, April 9, 2008 at 10:36am.

Solve in terms of sine and cosine:

sec(x) csc(x)- sec(x) sin(x)

so far I have:
1/cos(x) 1/sin(x) - 1/cos(x) sin(x)

I am not sure where to go to from there. The book says the answer is cot(x) or cos(x)/sin(x)

Thank you in advance.

Trig - drwls, Wednesday, April 9, 2008 at 10:49am
sec(x) csc(x)- sec(x) sin(x)
= (1/cos x)(1/sinx) - sinx/cosx
= [(1/sinx)-sinx]/cos x
= [1 - sin^2x]/(sin x cos x)
= cos^2 x/(sin x cos x)
= cosx/sinx = cot x
Trig - Dennis, Wednesday, April 9, 2008 at 11:03am
Dang, I see where I messed up. Thank you so much.
- Trig - Dennis, Wednesday, April 9, 2008 at 11:04am
  whoops, sorry everyone. The original message was supposed to be a reply to another post.

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