I need to find the perimeter of square that has a semicircle (located inside of the square) with a radius of 10 in and it appears that the square is 10 inches as well. I tried the equation 1/2*3.14*10= 15.7, but I don't think it is correct please help!!
If a complete semicircle is inside a square, it could be tangent to one side of the square and end at the midpoints of two adjacent sides. It would then have a radius of 10, the side of the square would be 20 long and the square's perimeter would be 80.
I still don't quite understand.
To find the perimeter of the square with a semicircle inside, you'll need to add the lengths of all four sides of the square to the semicircle's circumference.
First, let's find the perimeter of the square. Since all sides of a square are equal in length, you can simply multiply the length of one side by 4. In this case, the length of one side is given as 10 inches, so the perimeter of the square would be 10 inches * 4 = 40 inches.
Next, let's find the circumference of the semicircle. The formula for the circumference of a circle is 2πr, where r is the radius. In this case, the radius is given as 10 inches. So the circumference of the semicircle would be (2 * 3.14 * 10) / 2 = 3.14 * 10 = 31.4 inches.
Finally, to find the total perimeter, you'll add the perimeter of the square and the circumference of the semicircle: 40 inches + 31.4 inches = 71.4 inches.
Therefore, the correct answer is 71.4 inches, not 15.7 inches as you thought.