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April 18, 2014

April 18, 2014

Posted by **BP** on Monday, April 7, 2008 at 10:23pm.

log y = mx+ c

This would be y = 10^(mx+c) right?

- Maths (Logs) -
**Reiny**, Monday, April 7, 2008 at 10:51pm1. right

2 compare y = 10^(mx+c) right with y = a(b)^x

a=1, b=10 and x= mx+c

so it fits the model.

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