Posted by natash on Monday, April 7, 2008 at 8:12pm.
If 20.0mL of .2019M HCI requires 39.63mL of a NaOH solution for complete neutralization, what is the concentration of the NaOH solution? how many significant figures are justified in the answer?

chemacid base titrations  DrBob222, Monday, April 7, 2008 at 8:36pm
HCl + NaOH ==> NaCl + H2O
mols HCl used = L x M = 0.0200 L x 0.2019 M = ??
mols NaOH (from the equation it is a 1:1 ratio of HCl to NaOH; therefore, mols NaOH must be the same as that for HCl).
mols NaOH = L x M
You have L (0.03963 mL) and you have mols (from HCl), calculate M NaOH. You can have as many s.f. as the least number in your calculations; therefore, you may have 3 since 20.0 mL has three.
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