Posted by **Ross** on Monday, April 7, 2008 at 8:01pm.

Calculate the pH of the following aqueous solutions:

1.00 mol/L sulfuric acid

H+ = 1.00 M for the first ionization

THe second one is guided by K2

K2 = (H+)(HSO4-)/(HSO4-)

Plugging in K2 as follows:

H+ = 1.00 + x

SO4- = x

HSO4= 1.00 - x

Can someone please solve for x ?

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