Posted by david on Monday, April 7, 2008 at 12:24pm.
delta T = Kb*m
m = 18/62 = 0.29 mols
molality = 0.29/0.15 = 1.93 m
delta T = 1.86 x 1.93 = 3.6 degrees.
The normal freezing point is zero, so the new freezing point must be 0.0 - 3.6 = -3.6. I suspect that's your problem. You are stopping at delta T which IS 3.6 but the freezing point is -3.6 C.
thanks sooo much
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