April 16, 2014

Homework Help: math

Posted by alex on Monday, April 7, 2008 at 9:02am.

the problem is
2cos^2x + sinx-1=0

the directions are to "use an identity to solve each equation on the interval [0,2pi).

This is what i've done so far:



cos2x + sinx =0

1 - 2sin^2x + sinx = 0



I think i'm supposed to factor it next but i'm not sure?


would doing that step be correct?

Answer this Question

First Name:
School Subject:

Related Questions

math - solve each equation for 0=/<x=/<2pi sin^2x + 5sinx + 6 = 0? how do ...
trig - find the exact solutions 2cos^2x+3sinx=0 the way it stands, that is a "...
Trig - Verify the identity: tanx(cos2x) = sin2x - tanx Left Side = (sinx/cosx)(...
math - tanx+secx=2cosx (sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx ...
Trig Help - Prove the following: [1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx...
Math (trigonometry) - Trigonometry identities are so hard... I need some help ...
Trig....... - I need to prove that the following is true. Thanks (2tanx /1-tan^x...
Mathematics - Trigonometric Identities - Prove: sin^2x - sin^4x = cos^2x - cos^...
Pre-Calculus - Find all solutions to the equation in the interval [0, 2pi) cos4x...
Math-gr12 - How would I solve this equation for x in the interval 0<x<2pi ...