Posted by Laura on Saturday, April 5, 2008 at 4:14pm.
HNO2 ==> H^+ + NO2^-
Initial:
(HNO2) = 0.2
(H^+) = 0
(NO2^-) = 0
Ka = (H^+)(NO2^-)/(HNO2)
If 5.8% ionized, then after ionization:
(H^+) = 0.2 x 0.058 = ??
(NO2^-) = 0.2 x 0.058 = ??
(HNO2) = 0.2 x (1-0.058) = ?? (Note: If soln is 5.8% ionized than unionized is 100 - 5.8 = 94.2% OR 1.00 - 0.058 = 0.942).
Plug these values into Ka expression above and solve for Ka.
Calculate the Ka of nitrous acid if a 0.200 mol/L solution at equilibrium at SATP has a percent ionization of 5.8%
For Further Reading
chemistry - DBob222, Saturday, April 5, 2008 at 4:50pm
HNO2 ==> H^+ + NO2^-
Initial:
(HNO2) = 0.2
(H^+) = 0
(NO2^-) = 0
Ka = (H^+)(NO2^-)/(HNO2)
If 5.8% ionized, then after ionization:
(H^+) = 0.2 x 0.058 = ??
(NO2^-) = 0.2 x 0.058 = ??
(HNO2) = 0.2 x (1-0.058) = ?? (Note: If soln is 5.8% ionized than unionized is 100 - 5.8 = 94.2% OR 1.00 - 0.058 = 0.942).
Plug these values into Ka expression above and solve for Ka.
Here is my work:
Ka = (H^+)(NO2^-)/(HNO2)
= (0.0116)(0.0116) / (0.1884)
= 1.34 X 10^-4 / (0.1884)
= 7.14 X 10^-4
My answer is still wrong:( Is there a step I missed?
Related Questions
chemistry - Caclulate the Ka of nitrous acid if a 0.200 mol/L solution at ...
Chemistry - Calculate the percent ionization of nitrous acid in a solution that ...
chemistry - 2- A 0.310 M solution of a weak acid, HX, has a pH of 2.53 a. Find ...
chemistry - A 0.25 mol/L solution of benzoic acid, KC7H5O2 and antiseptic also ...
Chemistry - Write the equation for the equilibrium that exists when nitrous acid...
chemistry - A 0.25 mol/L solution of benzoic acid, KC7H5O2 and antiseptic also ...
chemistry - Lactic acid, HC3H5O3(aq) is a weak acid that gives yougurt its sour ...
chemistry - A 0.25 mol/L solution of benzoic acid, KC7H5O2 and antiseptic also ...
chemistry - A 0.185 M solution of a monoprotic acid has a percent ionization of ...
Chemistry 104 - What is the percent ionization of a solution prepared by ...
For Further Reading
