Physics
posted by Robinson on .
The drawing shows a person (weight W = 592 N, L1 = 0.841 m, L2 = 0.410 m) doing pushups. Find the normal force exerted by the floor on each hand and each foot, assuming that the person holds this position. force on each hand N
force on each foot N
I post this eailer and O'm still not getting it. I read my book and i know we would be using the center og gravity equation. I also know L2 is the hand force and L1 is the force of each foot

L1 and L2 are not forces; they describe locations where forces are applied. Between what points are the lengths L measured? Where is the person's center of mass?
I can visualize the problem but not the notation you are using.
The sum of the forces on arms and legs equals the person's weight. The distances of hands and feet from the center of mass determines how the forces are distributed between hands and feet. Set the moment about hands. feet or the center of mass equal to zero for the second equation you need. 
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