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October 25, 2014

Homework Help: chemistry

Posted by Tim's Titration Lab on Friday, April 4, 2008 at 5:07pm.

Trial 1

Volume of HCL is 2.51 mL

Molarity of the HCL is 0.10 M

Mols HCL = L x M

= 0.0251 L x 0.10 M

= 0.00251 mol/L

The equation for the titration is
Ca()H)2 + 2HCL --> CaCl2 + 2H2O

I will now take 0.5 mols HCl to give mols of OH-

0.00251 mol/L x 0.5 = 0.001255 mol/L

mols OH- / volume of the sample = OH- in mols/L

Don't I already have mols OH- in mols/L(0.001255 mol/L)?

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