Posted by Chaz on .
A 3.8 kg ball is swung in a horizontal circle at the end of a 1.5 meter rope. If the tension in the rope is kept constant at 79 N, what is the period of rotation, T?

Physics 
bobpursley,
Well, ignoring gravity (gravity makes the ball swing downward, the rope makes an angle, which changes the radius of rotation), then
tension= massball*v^2/r=m(2PIr/T)^2 /r
do the algebra, and solve for Period T. 
Physics 
Anonymous,
Idk