Posted by **Chaz** on Friday, April 4, 2008 at 2:52pm.

A 3.8 kg ball is swung in a horizontal circle at the end of a 1.5 meter rope. If the tension in the rope is kept constant at 79 N, what is the period of rotation, T?

- Physics -
**bobpursley**, Friday, April 4, 2008 at 3:36pm
Well, ignoring gravity (gravity makes the ball swing downward, the rope makes an angle, which changes the radius of rotation), then

tension= massball*v^2/r=m(2PIr/T)^2 /r

do the algebra, and solve for Period T.

- Physics -
**Anonymous**, Monday, October 31, 2016 at 7:48pm
Idk

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