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November 26, 2014

November 26, 2014

Posted by **Jon** on Friday, April 4, 2008 at 12:10pm.

box from the other side with a force of 11.0 N at an angle of 40.0 above the horizontal. What is the net work done on the box if the displacement of the box is 14.5 m?

w=fdcos

11.4(14.5)cos40 get that value and add that to 11.0(14.5)cos40

answer: 2.49 x 10^2 J

- physics repost -
**bobpursley**, Friday, April 4, 2008 at 12:53pmI didnt check calc work, but thinking is correct.

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