# math

posted by
**Matt**
.

The question is; identify the center and the radius of the circle in this equation.

3x^2 - √ 3x + 3y^2 - y + 1/12 = 0

I ended up getting

C:(√ 3/6, 1/6)

and

R: √ 3/6

posted by
**Matt**
.

The question is; identify the center and the radius of the circle in this equation.

3x^2 - √ 3x + 3y^2 - y + 1/12 = 0

I ended up getting

C:(√ 3/6, 1/6)

and

R: √ 3/6