Posted by
**Matt** on
.

The question is; identify the center and the radius of the circle in this equation.

3x^2 - √ 3x + 3y^2 - y + 1/12 = 0

I ended up getting

C:(√ 3/6, 1/6)

and

R: √ 3/6

Wednesday

March 29, 2017
Posted by
**Matt** on
.

The question is; identify the center and the radius of the circle in this equation.

3x^2 - √ 3x + 3y^2 - y + 1/12 = 0

I ended up getting

C:(√ 3/6, 1/6)

and

R: √ 3/6

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