Do not solve, show possibilities of Descartes's rule of signs for roots.

4x^3-9x^2+6x+4=0

f(x)=4x^3-9x^2+6x=4
- + +
one change
=4(-x)^3-9(-x)^2+6(-x)+4
- + - +
three changes

Positive Negative Imaginary
2 1 0
1 2 0
3 possible roots

To determine the possibilities of roots for the given equation using Descartes's rule of signs, we need to examine the sign changes in the coefficients of the equation.

The equation we have is 4x^3 - 9x^2 + 6x + 4 = 0.

Let's break it down to analyze the sign changes:

1. First, let's consider the original equation, f(x) = 4x^3 - 9x^2 + 6x - 4:

- The coefficient of the first term (4x^3) is positive.
- The coefficient of the second term (-9x^2) is negative.
- The coefficient of the third term (6x) is positive.
- The constant term (-4) is negative.

From this, we can determine that:

- There is one sign change from positive to negative.
- There are two sign changes from negative to positive.

2. Next, we can apply Descartes's rule of signs to determine the possibilities of roots:

- The number of positive roots of the equation f(x) = 4x^3 - 9x^2 + 6x - 4 is equal to the number of sign changes when replacing x with -x (f(-x)) or an even value.

In f(-x), we substitute -x for x in the original equation:
f(-x) = 4(-x)^3 - 9(-x)^2 + 6(-x) - 4,
which simplifies to f(-x) = -4x^3 - 9x^2 - 6x - 4.

Counting the sign changes in f(-x):

- There are three sign changes from negative to positive.

- The number of negative roots of the equation f(x) = 4x^3 - 9x^2 + 6x - 4 is equal to the number of sign changes when replacing x with -x (f(-x)) or an odd value.

Counting the sign changes in f(-x):

- There are two sign changes from positive to negative.

Therefore, based on Descartes's rule of signs:

- The original equation has either one or three positive roots.
- The original equation has either two or no negative roots.

It's important to note that Descartes's rule of signs gives us possibilities for the number of positive and negative roots, but it doesn't provide us with the exact number of roots or their values. Additional techniques like factoring, synthetic division, or graphical methods may be needed to determine the exact values of the roots.