Tuesday
September 30, 2014

Homework Help: chemistry

Posted by Claus on Thursday, April 3, 2008 at 9:11pm.

AgCl <==> Ag^+ + Cl^-
NaCl ==> Na^+ + Cl^-

Ksp = (Ag^+)(Cl^-) = 1.8 x 10^-10
Let S = solubility of AgCl, then
(Ag^+) = S
(Cl^-) = S+0.01
Solve for S.
Note: A similar problem to this post (0.1 M NaCl instead of 0.01 M NaCl) was on a couple of days ago; the one who posted said that the answer came back incorrect. Check my work. Check myu thinking.


Should the continuing work look like this?
S = 1.8 x 10^-10 + 1
= 1.00?

Please help I am very confused

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