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November 23, 2014

November 23, 2014

Posted by **Gabe** on Thursday, April 3, 2008 at 7:33pm.

I am really confused on this one.

f(x)=(x-9)/(x^2-4), vertical

x^2-4=0 x=+-2 x=2&x=-2

x arrow oo or x arrow -oo

(-9/x)&(-4/x) approach 0

h(x)=(1/x)+0)/(1+0)=(0/1)=0

- Algebra -
**Anonymous**, Thursday, April 3, 2008 at 8:03pmHmm is it asking you to find only the vertical asymptotes? If so than you got them. The function has a vertical asymptote at -2 and 2. If you also have to find a horizontal asymptote than its 0 because the denominator has the highest power.

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