Homework Help: Algebra

Posted by Lynn on Thursday, April 3, 2008 at 5:47pm.

I am trying to find the real coefficients of the given roots. Did I do this right?

3,-9,3+2i

(x-3)(x+9)[x-(3+2i)][x-(3-2i)]=0
(x-3)(x+0)[(x-3)+2i][(x-3)-2i]=0
(x-3)(x+9)[(x-3)^2-2i^2]=0
(x-3)(x+9)(x^2-6x-8)=0
(x^4-71x^2+114x+216)=0
answer x^4-71x^2+114x+216=0

Algebra - Anonymous, Thursday, April 3, 2008 at 6:04pm
Hmm.. I never done this before but I think you are right for the most part. You made a mistake on (x-3)(x+9)(x^2-6x-8) = 0. (x-3)^2 - 2i^2 does not expand to x^2-6x-8.

x-3)^2 - 2i^2
x^2 - 6x + 9 + 2
x^2 - 6x + 11

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