Wednesday

April 16, 2014

April 16, 2014

Posted by **Lynn** on Thursday, April 3, 2008 at 5:47pm.

3,-9,3+2i

(x-3)(x+9)[x-(3+2i)][x-(3-2i)]=0

(x-3)(x+0)[(x-3)+2i][(x-3)-2i]=0

(x-3)(x+9)[(x-3)^2-2i^2]=0

(x-3)(x+9)(x^2-6x-8)=0

(x^4-71x^2+114x+216)=0

answer x^4-71x^2+114x+216=0

- Algebra -
**Anonymous**, Thursday, April 3, 2008 at 6:04pmHmm.. I never done this before but I think you are right for the most part. You made a mistake on (x-3)(x+9)(x^2-6x-8) = 0. (x-3)^2 - 2i^2 does not expand to x^2-6x-8.

x-3)^2 - 2i^2

x^2 - 6x + 9 + 2

x^2 - 6x + 11

**Related Questions**

Algebra 2 - Find a real plynomial equation with real coefficients that has the ...

Algebra - I have to rationalize the denominator of 2+3i/1+2i. I multiplyed this ...

PreCal - Find all real numbers x and y -2x-4-2yi=3x-2i 5x+2yi=-4+2i 5x=-4 so x=-...

math help people lik really desperate!! - ok i have to divide complex numbers: ...

check my work please! - ok i have to divide complex numbers: question is: 1-2i+i...

PreCal - Find all real numbers x and y so I'm a bit confused with the y solution...

Algebra 2 - When dealing with imaginary and complex numbers, are there 2 ...

can someone please help me? - simplify the following expressions involving ...

complex numbers and imaginary units - 2i/1+i your question probably says '...

PreCalc - 6.Given -2i is a root, determine all other roots of x^4-10x^3+42x^2-...