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April 1, 2015

April 1, 2015

Posted by **Lynn** on Thursday, April 3, 2008 at 5:47pm.

3,-9,3+2i

(x-3)(x+9)[x-(3+2i)][x-(3-2i)]=0

(x-3)(x+0)[(x-3)+2i][(x-3)-2i]=0

(x-3)(x+9)[(x-3)^2-2i^2]=0

(x-3)(x+9)(x^2-6x-8)=0

(x^4-71x^2+114x+216)=0

answer x^4-71x^2+114x+216=0

- Algebra -
**Anonymous**, Thursday, April 3, 2008 at 6:04pmHmm.. I never done this before but I think you are right for the most part. You made a mistake on (x-3)(x+9)(x^2-6x-8) = 0. (x-3)^2 - 2i^2 does not expand to x^2-6x-8.

x-3)^2 - 2i^2

x^2 - 6x + 9 + 2

x^2 - 6x + 11

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