Saturday

July 26, 2014

July 26, 2014

Posted by **Lynn** on Thursday, April 3, 2008 at 5:47pm.

3,-9,3+2i

(x-3)(x+9)[x-(3+2i)][x-(3-2i)]=0

(x-3)(x+0)[(x-3)+2i][(x-3)-2i]=0

(x-3)(x+9)[(x-3)^2-2i^2]=0

(x-3)(x+9)(x^2-6x-8)=0

(x^4-71x^2+114x+216)=0

answer x^4-71x^2+114x+216=0

- Algebra -
**Anonymous**, Thursday, April 3, 2008 at 6:04pmHmm.. I never done this before but I think you are right for the most part. You made a mistake on (x-3)(x+9)(x^2-6x-8) = 0. (x-3)^2 - 2i^2 does not expand to x^2-6x-8.

x-3)^2 - 2i^2

x^2 - 6x + 9 + 2

x^2 - 6x + 11

**Related Questions**

plllllls heeeeeeelp math - Let f(x)=3^(171x−3)−3^(114x+2)+3^(57x+3...

Algebra - Can someone tell me how they got the answer? Find a polynomial ...

math - 25.83/3.71x/5.3 find unknown proportion. show steps to solve

chemistry - A student estimated the volume of liquid in a beaker as 200 mL. When...

pre-calculus - find the cube roots of -216 answer in polar form

Algebra 2 - Find a real plynomial equation with real coefficients that has the ...

pre-calculus - find the cube roots of -216 answer in polar form and complex

Trigenometry Math - Using the factors (-5x+4) and (x+1), find the remaining ...

Math (Trigenometry) - Using the factors (-5x+4) and (x+1), find the remaining ...

Algebra II - Which describes the number and type of roots of the equation x^2 -...