Posted by **John** on Thursday, April 3, 2008 at 5:40pm.

min/max point

minimum or maximum

f(x)=2x^2+8x-2

a=2

x=(-b)/(2a)=(-8)/(2)(2)=-4

x=-4

y=2(-4)^2+8(-4)-2

2(16)-32-2

32-32-2

y=-2

(-4,-2)

axis of symmetry is x=-4

range[-2,oo]

minimum value -2

- Algebra -
**Anonymous**, Thursday, April 3, 2008 at 5:45pm
I think you messed up when trying to find the axis of symmetry. There's a small calculation error there and it seems to have thrown off all your answers. However, your work overall is correct.

- Algebra -
**roro**, Thursday, April 3, 2008 at 7:08pm
when you used the calculator to find (-8)/(2)(2) you did not consider the order of operations you must multiply 2 by 2 before you divide -8 by the answer, otherwise your method is correct

- Algebra -
**John**, Thursday, April 3, 2008 at 9:09pm
My range changes to -10 and the axis is x=-2, and min value is -10?

- Algebra -
**Anonymous**, Thursday, April 3, 2008 at 9:48pm
Yes.

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