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March 26, 2017

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The melting point of a solid is 90.0 d/C. What is the heat required to change 2.5 kg of this solid at 40.0 d/C to a liquid? The specific heat of the solid is 390 J/kg-K and its heat of fusion is 4000 J/kg.

I got 2 different answers 2 different ways:

2.5(50)(4000) which is 5.0 x 10^5 J or, 2.5(4000) which is 1.0 x 10^4 J

  • physics - ,

    This is two problems rolled into one.
    q1 = heat required to raise T of solid from 40.0 C to 90.0 C.
    q1 = mass x specific heat x delta T.

    q2 = heat required to melt the solid once the T has reached 90.0 C.
    q2 = mass x heat of fusion.

    Total heat = q1 + q2.

  • physics - ,

    I read what you said but could it be this also?

    390*2.5*50

    specific heat x mass x change in temperature.

    answer: 4.9 x 10^4 J

  • physics - ,

    No, it can't be that.
    390*2.5*50 is q1. That's the amount of heat necessary to raise the temperature of the solid from 40 C to its melting point of 90 C. But the total heat is that amount PLUS the amount necessary to melt the solid. That is q2 which is 2.5 kg x 4000 J/kg.
    Therefore, the total is
    (390*2.5*50) + (2.5*4000) = ??

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