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Calculate the solubility of silver chloride in a 0.010 mol/L solution of sodium chloride at 25 degrees Celsius. At SATP, Ksp AgCl(s) = 1.8 x 10^-10

  • chemistry - ,

    AgCl <==> Ag^+ + Cl^-
    NaCl ==> Na^+ + Cl^-

    Ksp = (Ag^+)(Cl^-) = 1.8 x 10^-10
    Let S = solubility of AgCl, then
    (Ag^+) = S
    (Cl^-) = S+0.01
    Solve for S.
    Note: A similar problem to this post (0.1 M NaCl instead of 0.01 M NaCl) was on a couple of days ago; the one who posted said that the answer came back incorrect. Check my work. Check myu thinking.

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