Posted by **Tasha** on Thursday, April 3, 2008 at 5:08am.

A child is twirling a 0.0116 kg ball on a string in a horizontal circle whose radius is 0.102 m. The ball travels once around the circle in 0.560 s.

(a) Determine the centripetal force acting on the ball.

N

(b) If the speed is doubled, does the centripetal force double?

yes

no

If not, by what factor does the centripetal force increase?

I was able to work the problem but i'm not sure what it means by factor for the third part of the problem. Please help.

- Physics -
**drwls**, Thursday, April 3, 2008 at 6:35am
Centripetal force is

M V^2/R

In your case V = 2 pi R /(0.56 s) = 1.1144 m/s, so

Force = (0.0116)(1.1144)^2/(0.102)= ? N

If V is charged to 2V, the Force becomes 4 times as large, because the 2 gets squared. The factor they are looking for is 4.

## Answer this Question

## Related Questions

- Physics - A child is twirling a 0.0116 kg ball on a string in a horizontal ...
- physics - a child is twirling a 0.0120 kg ball on a string in a horizontal ...
- physics - A child is twirling a 0.0165-kg ball on a string in a horizontal ...
- physics - A child is twirling a 0.0100 kg ball on a string in a horizontal ...
- Physics - A child is twirling a 0.0120-kg plastic ball on a string in a ...
- Physics - A child twirling a 0.0120kg ball on a string in a horizontal circle ...
- physics - A ball on the end of a string is whirled around in a horizontal circle...
- Physics - A ball on the end of a string is whirled around in a horizontal ...
- Physics - A ball on the end of a string is whirled around in a horizontal ...
- physics - A ball on the end of a string is whirled around in a horizontal circle...