Posted by **Tasha** on Wednesday, April 2, 2008 at 11:44pm.

A car travels at a constant speed around a circular track whose radius is 2.5 km. The car goes once around the track in 430 s. What is the magnitude of the centripetal acceleration of the car?

- Physics -
**drwls**, Thursday, April 3, 2008 at 2:01am
The centripetal acceleration is

a = V^2/R,

and the velocity V is given by

2*pi*R = V*P

where P is the period of 430 s.

The second equation can be used to eliminate the variable V, leaving you with

a = [2 pi R/P]^2/R = 4 pi^2 R/P^2

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