Posted by Tasha on Wednesday, April 2, 2008 at 11:44pm.
A car travels at a constant speed around a circular track whose radius is 2.5 km. The car goes once around the track in 430 s. What is the magnitude of the centripetal acceleration of the car?

Physics  drwls, Thursday, April 3, 2008 at 2:01am
The centripetal acceleration is
a = V^2/R,
and the velocity V is given by
2*pi*R = V*P
where P is the period of 430 s.
The second equation can be used to eliminate the variable V, leaving you with
a = [2 pi R/P]^2/R = 4 pi^2 R/P^2
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