posted by Tasha on .
A car travels at a constant speed around a circular track whose radius is 2.5 km. The car goes once around the track in 430 s. What is the magnitude of the centripetal acceleration of the car?
The centripetal acceleration is
a = V^2/R,
and the velocity V is given by
2*pi*R = V*P
where P is the period of 430 s.
The second equation can be used to eliminate the variable V, leaving you with
a = [2 pi R/P]^2/R = 4 pi^2 R/P^2