A 6110-kg bus traveling at 20.0 m/s can be stopped in 24.0 s by gently applying the brakes. What is the average force exerted on the bus in this stop?
I can't figure this one out
(Momentum change)= impulse
= (Force) x (time)
Force = M V/(time)
6110 * 20 whole thing divided by 24 = 5.09*10^3N
To find the average force exerted on the bus, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration. In this case, we need to find the acceleration of the bus to determine the force applied.
First, let's calculate the deceleration (negative acceleration) of the bus using the formula acceleration = change in velocity / time taken.
change in velocity = final velocity - initial velocity
= 0 - 20.0 m/s (since the bus is stopped)
acceleration = (0 - 20.0 m/s) / 24.0 s
= -20.0 m/s / 24.0 s
= -0.833 m/s^2
Now that we have the acceleration, we can find the average force applied using the formula force = mass * acceleration.
force = 6110 kg * -0.833 m/s^2
= -5086.83 N
The negative sign indicates that the force is directed opposite to the motion of the bus. Therefore, the average force exerted on the bus during this stop is approximately 5086.83 Newtons in the opposite direction of the bus's motion.
To find the average force exerted on the bus during its stop, you can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration.
However, in this case, we don't have information about the acceleration directly. Instead, we have the initial velocity, final velocity, and the time taken to stop the bus. We can use these to calculate the acceleration using the formula:
acceleration (a) = (final velocity - initial velocity) / time
Given:
Mass (m) = 6110 kg
Initial velocity (u) = 20.0 m/s
Final velocity (v) = 0 (since the bus comes to a complete stop)
Time (t) = 24.0 s
Substituting the values into the formula:
acceleration (a) = (0 - 20.0) m/s / 24.0 s
Simplifying:
a = -20.0 m/s / 24.0 s
Now, we have the acceleration. We can use the formula F = ma to find the force:
Force (F) = mass (m) * acceleration (a)
Substituting the values:
F = 6110 kg * (-20.0 m/s / 24.0 s)
Calculating:
F = -5085.83 N
The negative sign indicates that the force is acting in the opposite direction of the bus's motion. However, for the purposes of magnitude, we can remove the negative sign, giving us an average force of approximately 5085.83 N exerted on the bus during its stop.