Posted by Kendra on Wednesday, April 2, 2008 at 9:28pm.
I will be happy to critique your thinking.
The sum of the moments about the piviot has to be zero.
Let the heavier child be x meters from the fulcrum. The lighter child will be 2.5 - x meters from the fulcrum.
For equilibrium,
437.7 x = 237.1 (2.5 -x)
Solve for x.
674.8 x = 592.75
x = 0.88 m
Related Questions
Physics - A 450.8 N child and a 101.0 N child sit on either end of a 2.2 m long ...
Physics - A 450.8 N child and a 101.0 N child sit on either end of a 2.2 m long ...
physics - A playground seesaw is exactly 3.00 m long. A little girl who weighs ...
Math - Two children sit on a seesaw that is 14 ft long. One child weighs 95 lb, ...
physics - A fulcrum is placed under the center of a uniform 4.00m long, 3.00kg ...
physics - Two children seat themselves on a seesaw, the one on the left has a ...
Physics?? - Two children sit 2.60 m apart on a very low-mass horizontal seesaw ...
MATH - HASAN MADE A MODEL FOR 437 HUNDREDS, 3 TENS,AND 7.WHAT ARE TWO OTHER WAYS...
Physics - A child sits on one side of a teeter totter of length 7.60 m, a ...
physics - Suppose a 34.5-kg child sits 1.17 m to the left of center on the same ...
For Further Reading
