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A 437.7 N child and a 237.1 N child sit on either end of a 2.5 meter long seesaw.
How far from the 437.7 N child should the pivot be placed to ensure rotational equilibrium? disregard the mass of the seesaw. answer in units of m.

  • Physics - ,

    I will be happy to critique your thinking.

    The sum of the moments about the piviot has to be zero.

  • Physics - ,

    Let the heavier child be x meters from the fulcrum. The lighter child will be 2.5 - x meters from the fulcrum.
    For equilibrium,
    437.7 x = 237.1 (2.5 -x)
    Solve for x.
    674.8 x = 592.75
    x = 0.88 m

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