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posted by Jon on Wednesday, April 2, 2008 at 9:12pm.
A 1.00-kg ball is attached to a string of 0.50 m and swung in a horizontal circle with a velocity of 2.00 m/s. Find the centripetal acceleration. ac=v^2/r = 2.00^2/.50 = 8.0 m/s^2
That is correct. :-)
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