Posted by **meg** on Wednesday, April 2, 2008 at 7:57pm.

Directions: The focus and directrix of a parabola are given. Write an equation for each parabola.

(2,4) y = 6

May you explain the procedures on how to solve this equation? Please be detailed on each step.

- algebra 2 -
**Reiny**, Wednesday, April 2, 2008 at 10:24pm
I assume you have to use the basic definition of a parabola as the set of points equidistant from the focal point (2,4) and the line y=6

Make a sketch and let P(x,y) be any point on the parabola

so √((x-2)^2 + (y-4)^2) = √(y-6)^2

square both sides

(x-2)^2 + (y-4)^2 = (y-6)^2

x^2 - 4x + 4 + y^2 - 8y + 16 = y^2 - 12y + 36

y = -(1/4)x^2 + x + 4

## Answer this Question

## Related Questions

- algebra - 6. Find the equation of each parabola described below. a) parabola ...
- maths - Given that the equation of the parabola is 5y^2 + 24x = 0. Find (1)The ...
- algebra - A few more question Id like for someone to check please. 1) what are ...
- Math - determine vertex, focus and directrix of parabola. then graph the ...
- Pre Cal - write the equations of the parabola, the directrix, and the axis of ...
- Algebra - Can someone tell me if I am right? I need to find the equation of a ...
- math - determine vertex, focus and directrix of parabola. then graph the ...
- algebra problem - I need to find the equation of a parabola. I am not sure if ...
- Math - determine vertex, focus and directrix of parabola. then graph the ...
- College Algebra - Find the standard form of the equation of the parabola with ...