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December 18, 2014

December 18, 2014

Posted by **meg** on Wednesday, April 2, 2008 at 7:57pm.

(2,4) y = 6

May you explain the procedures on how to solve this equation? Please be detailed on each step.

- algebra 2 -
**Reiny**, Wednesday, April 2, 2008 at 10:24pmI assume you have to use the basic definition of a parabola as the set of points equidistant from the focal point (2,4) and the line y=6

Make a sketch and let P(x,y) be any point on the parabola

so √((x-2)^2 + (y-4)^2) = √(y-6)^2

square both sides

(x-2)^2 + (y-4)^2 = (y-6)^2

x^2 - 4x + 4 + y^2 - 8y + 16 = y^2 - 12y + 36

y = -(1/4)x^2 + x + 4

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