Friday

December 19, 2014

December 19, 2014

Posted by **Will** on Tuesday, April 1, 2008 at 3:51pm.

- Physics -
**drwls**, Tuesday, April 1, 2008 at 4:39pmTheir initial velocities are in a ratio V1/V2 = m2/m1

Their kinetic friction forces are in a ratio

F1/F2 = M1/M2

Gliding time t is proportional to

V/a = V m/F

Gliding distance D is proportional to

V*t = V^2*m/F

D1/D2 = 3 = [V1^2*m1/F1)][m2/(F2*V2^2)]

= (V1/V2)^2*(m1/m2)*F2/F1

= (m2/m1)^2

m2/m1 = 3^1/2 = 1.732

m1/m2 = 0.577

**Answer this Question**

**Related Questions**

Physics - Two ice skaters have masses m1 and m2 and are initially stationary. ...

physics - Two ice skaters have masses m1 and m2 and are initially stationary. ...

Physics - Two ice skaters, with masses of 30kg & 85 kg are at the center of a ...

Physics - Two identical ice skaters are holding onto opposite ends of a very ...

physics - In the figure, two skaters, each of mass 58.0 kg, approach each other ...

Physics - two skaters, each of mass 55 kg, approach each other along parallel ...

physic - two figure skaters, one weighting 625N and the other 725N,push off ...

physics - Two ice skaters stand at rest in the center of an ice rink. When they ...

physics 2!!** - Two ice skaters stand at rest in the center of an ice rink. When...

Physics - Three particles have identical masses and identical inital velocities...