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March 28, 2015

March 28, 2015

Posted by **Will** on Tuesday, April 1, 2008 at 3:51pm.

- Physics -
**drwls**, Tuesday, April 1, 2008 at 4:39pmTheir initial velocities are in a ratio V1/V2 = m2/m1

Their kinetic friction forces are in a ratio

F1/F2 = M1/M2

Gliding time t is proportional to

V/a = V m/F

Gliding distance D is proportional to

V*t = V^2*m/F

D1/D2 = 3 = [V1^2*m1/F1)][m2/(F2*V2^2)]

= (V1/V2)^2*(m1/m2)*F2/F1

= (m2/m1)^2

m2/m1 = 3^1/2 = 1.732

m1/m2 = 0.577

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