An elevator is moving up with an acceleration of 3.36 m/s^2. What would be the apparent weight of a 64.2 kg man in the elevator?

A)215.71 N
B)413.45 N
C)844.87
D)Need more information

ok I got 847.44 but as you can see that's not an answer choice so my guess is D, need more information.

The answer is M(a + g) = 64.2(9.806 + 3.36) = 845.3 N

The closest answer is C. You will get their exact "C" answer if you use 9.8 m/s^2 for g.

To determine the apparent weight of the man in the elevator, we need to consider the force acting on him.

The weight of an object is given by the equation W = m*g, where m is the mass of the object and g is the acceleration due to gravity (approximately 9.8 m/s^2 on Earth).

In this case, since the elevator is moving up with an acceleration of 3.36 m/s^2, the apparent weight of the man can be calculated by considering the net force acting on him.

The net force, F_net, can be determined using Newton's second law, which states that F_net = m*a, where a is the acceleration of the object.

In this scenario, the net force acting on the man is the difference between his apparent weight (F_apparent) and his actual weight (F_weight). Therefore, we can write:

F_net = F_apparent - F_weight

Since the elevator is moving up, the apparent weight of the man will be greater than his actual weight. We can express this as:

F_apparent = F_weight + F_net

Substituting for F_net and rearranging the equation, we get:

F_apparent = m * (g + a)

Now we can calculate the apparent weight of the man:

F_apparent = 64.2 kg * (9.8 m/s^2 + 3.36 m/s^2)

Simplifying this expression, we find:

F_apparent = 64.2 kg * 13.16 m/s^2

F_apparent = 844.87 N

Therefore, the apparent weight of the man in the elevator is approximately 844.87 N.

Since none of the answer choices match this value exactly, it appears that D) Need more information is the correct choice.