Posted by Kelly on .
An electron is moving through a magnetic field whose magnitude is 8.70*10^4 T. The electron experiences only a magnetic force and has an acceleration of magnitude 3.50*10^14 m/s^2. At a certain instant, it has a speed of 6.80*10^6m/s. Determine the angle (less than 90degrees) between the electron's velocity and the magnetic field.
Can anyone please give me some ideas to do it? THANKS!

physics 
bobpursley,
If you know acceleration, you know Force: F=ma. Knowing force, look at the magnetic force equation (sinThetaBqv?) and solve for velocity

physics 
artit,
chup