Posted by Cupcake on Tuesday, April 1, 2008 at 1:26pm.
I do not understand implicit differentiation. One of the problems are: find y' by implicit differentiation xy+2x+3x^2=4.
I would appreciate any help that can be offered.

Calculus 1  implicit differentiation  drwls, Tuesday, April 1, 2008 at 1:38pm
Just differtiate each term with respect to x, remembering that y is a function of x. You often end up with an expression for y' that involves both x and y, but is is a valid equation. You may have to evaluate y before you can calculate y'. Here is what you get:
x*dy/dx + y + 2 + 6x = 0
dy/dx = (y + 2 + 6x)/x
= (y+2)/x 6

Calculus 1  implicit differentiation  Cupcake, Tuesday, April 1, 2008 at 2:28pm
thank you
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