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Calculus 1 - implicit differentiation

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I do not understand implicit differentiation. One of the problems are: find y' by implicit differentiation xy+2x+3x^2=4.

I would appreciate any help that can be offered.

  • Calculus 1 - implicit differentiation - ,

    if you can do the basic rules like the product rule, then you can do implicit differentiating.

    xy+2x+3x^2=4

    Let me explain term by term

    xy is a product, so when you differentiate
    you get
    x(dy/dx) + y(dx/dx)
    or
    x(dy/dx) + y since dx/dx = 1

    2x would give you 2 and
    3x^2 would give you 6x (really it was 6x(dx/dx) which is 6x(1) or 6x)

    and of course the derivative of 4 is zero
    so you would have

    x(dy/dx) + y + 2 + 6x = 0

    solving this for dy/dx you would finally have

    dy/dx = (-6x - y - 2)/x

    You will get questions where there is a dy/dx in several terms.
    In that case bring all those terms to one side of your equation, factor out the dy/dx, and solve for dy/dx that way.

    the key this is to remember:
    if you differentiate an x term you also get a dx/dx hanging around, which is 1, so you don't have to write it, but
    if you differentiate a y term you would get a dy/dx hanging around.

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