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March 27, 2017

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i have a problem in dis sum from complex numbers

prove that
(1+sinA+icosA)/(1-sinA-icosA)=i(secA+tanA)

  • algebra - ,

    multiply the left side by (1-sinA+icosA)/(1-sinA+icosA)
    expand and simply it down to

    icosA/(1+sinA)

    multiply that by (1-sinA)/(1-sinA)
    expand again and simplify down to

    i(1-sinA)/cosA

    = i(1/cosA - sinA/cosA)
    = i(secA - tanA)
    = Right Side

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