15)If a horizontal force applied on a resting object is greater than the force of friction, the object will.
accelerate in the direction of the applied force
16)You are pushing a 55N lawnmower across the yard. Its handle makes a 55 degree angle with the ground. What force are you exerting on the handle?
95.89 N
17)Two men pull a 31 kg box with forces 9.7 N and 7.6 N in both directions. Find the resultant acceleration of the box and the direction in which the box moves.
2.1 m/s^2 to the left
15) If a horizontal force applied on a resting object is greater than the force of friction, the object will accelerate in the direction of the applied force. This is because the force of friction opposes the motion of the object, and if the applied force overcomes the force of friction, the object will begin to move in the direction of the applied force.
16) To calculate the force you are exerting on the handle of a lawnmower, you can use the formula:
Force = Applied Force x cos(angle)
Given that the applied force is 55N and the angle is 55 degrees, the calculation would be:
Force = 55N x cos(55 degrees)
≈ 55N x 0.5736
≈ 31.55 N
Therefore, you are exerting a force of approximately 31.55 N on the handle of the lawnmower.
17) To find the resultant acceleration of the box, you need to calculate the net force acting on it and then use Newton's second law, which states that the acceleration is equal to the net force divided by the mass of the object.
The net force can be calculated by finding the vector sum of the two forces:
Net Force = 9.7 N - 7.6 N
= 2.1 N
Now, using the given mass of 31 kg, the resultant acceleration can be calculated:
Acceleration = Net Force / Mass
= 2.1 N / 31 kg
≈ 0.068 m/s^2
The direction in which the box moves is determined by the net force. Since the net force is positive (+2.1 N), the box moves to the left.
To solve these physics problems, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.
15) The object will accelerate in the direction of the applied force. In this case, if the horizontal force applied is greater than the force of friction, the object will move in the direction of the applied force. To calculate the acceleration, divide the net force by the mass of the object.
16) To find the force exerted on the handle, we need to break down the given force of 55 N into its horizontal and vertical components. The force exerted on the handle is equal to the horizontal component. We can find the horizontal component by multiplying the given force by the cosine of the angle between the force and the horizontal plane. In this case, the angle is 55 degrees. So the force exerted on the handle is 55 N * cos(55°) = 95.89 N.
17) To find the resultant acceleration of the box, we need to calculate the net force acting on the box. The net force is the vector sum of the two forces applied by the men. Since both forces are in opposite directions, we need to subtract the smaller force from the larger force to find the net force. The net force is 9.7 N - 7.6 N = 2.1 N. To find the resultant acceleration, divide the net force by the mass of the box. The resultant acceleration is 2.1 N / 31 kg = 0.068 m/s^2. Since the net force and the resultant acceleration are both to the left, the box will move to the left.