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December 20, 2014

December 20, 2014

Posted by **Jon** on Monday, March 31, 2008 at 3:50pm.

11)A race car travels on a racetrack at 38 m/s and slows at a constant rate to a velocity of 20 m/s over 10 s. How far does it move during this time?

d=Vi(t)+1/2(a)(t^2)

d=38(10)+(1/2)(1.8)(100)

I got 470 meters but my choices are:200,290,380,and 760 so I chose 380

- physics repost -
**bobpursley**, Monday, March 31, 2008 at 4:21pmOn 9) I will be happy to critique your thinking.

on 11) distance while slowing?

average velocity=29

distance=avgvelocity*time....

On your work, a should be negative....

- physics repost -
**Jon**, Monday, March 31, 2008 at 4:28pm9)I multiplied total distance 85 miles times total time of 70 min. and got 1.21 mi/hr

- physics repost typo -
**Jon**, Monday, March 31, 2008 at 4:54pmI divided of course

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