Homework Help: another pre cal (logs)

Posted by Deb on Monday, March 31, 2008 at 1:14am.

write as a single log

log(underscore3)(3x-6)-[log(underscore3)(x^2-4)+log(underscore3)81]

thanks

another pre cal (logs) - Reiny, Monday, March 31, 2008 at 1:17am
according to your basic laws of logs your expression is

log₃ ((3x-6)(x^2 - 4)/81)
sorry, try again - Reiny, Monday, March 31, 2008 at 1:19am
I misread you + and - signs

should be

log₃ (81(3x-6)/(x^2 - 4))
- sorry, try again - Reiny, Monday, March 31, 2008 at 1:22am
  which reduces to
  
  log₃ 243/(x-2) , x > 2
another pre cal (logs) - Deb, Monday, March 31, 2008 at 1:37am
Thank you

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