# Math

posted by on .

x^2+6x+27
m^2-m-12

• Math - ,

What are you supposed to do? Factor?

• Math - ,

yes

• Math - ,

yes factor

• Math - ,

m^2 - m - 12 is simply (x-4)(x+3)

x^2 + 6x + 27 is a weird one if you only just started learning how to factor. Not to mention the factors contain imaginary numbers. You can solve it in two ways. The first way I forgot -.-. The second is to use the quadratic formula which goes (-b+sqrt(b^2-4ac))/(2a) and/or (-b-sqrt(b^2-4ac))/(2a).
I'm going to rewrite the equation as such:
1x^2 + 6x^1 + 27x^0
ax^2 + bx^1 + cx^0
a is the coefficient of x^2 which is 1. b is the coefficient of x which is 6 and c is the coefficient of x^0 which is 27.

So substitute the values of a, b, and c into the quadratic formula and you get the roots. Which are -3 (+/-) 3sqrt(-2). Then subtract them from x and you get your factors which are (x+3-3sqrt(-2)) and (x+3+3sqrt(-2)).

Now that I finished it's ridiculously silly for your teacher to ask this of you if you just learned to factor. Or if you are really behind than you need to study -.- since factoring is basic stuff. Well unless you meant x^2-6x-27 than that's a lot more simpler whose factors are (x-9)(x+3).