Posted by joyce on Sunday, March 30, 2008 at 10:57pm.
x^2+6x+27
m^2m12

Math  Anonymous, Sunday, March 30, 2008 at 11:02pm
What are you supposed to do? Factor?

Math  joyce, Sunday, March 30, 2008 at 11:19pm
yes

Math  joyce, Sunday, March 30, 2008 at 11:40pm
yes factor

Math  Original poster, Sunday, March 30, 2008 at 11:47pm
m^2  m  12 is simply (x4)(x+3)
x^2 + 6x + 27 is a weird one if you only just started learning how to factor. Not to mention the factors contain imaginary numbers. You can solve it in two ways. The first way I forgot .. The second is to use the quadratic formula which goes (b+sqrt(b^24ac))/(2a) and/or (bsqrt(b^24ac))/(2a).
I'm going to rewrite the equation as such:
1x^2 + 6x^1 + 27x^0
ax^2 + bx^1 + cx^0
a is the coefficient of x^2 which is 1. b is the coefficient of x which is 6 and c is the coefficient of x^0 which is 27.
So substitute the values of a, b, and c into the quadratic formula and you get the roots. Which are 3 (+/) 3sqrt(2). Then subtract them from x and you get your factors which are (x+33sqrt(2)) and (x+3+3sqrt(2)).
Now that I finished it's ridiculously silly for your teacher to ask this of you if you just learned to factor. Or if you are really behind than you need to study . since factoring is basic stuff. Well unless you meant x^26x27 than that's a lot more simpler whose factors are (x9)(x+3).