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September 2, 2014

September 2, 2014

Posted by **Lin** on Sunday, March 30, 2008 at 9:51pm.

pi[{3ln(3)^2 - 6ln (3) + 6} - {ln(1)^2 - 2 ln(1) + 2}]

- Calculus -
**drwls**, Sunday, March 30, 2008 at 10:25pmThat does not look like a function to be integrated. It looks like a number to be calculated. You can start out simplifying it by recognizing that

ln(1) = 0.

When you write ln(3)^2, do you mean

[ln(3)]^2 or ln[3^2]? They are not the same. I will assume the latter.

ln [3^2] = 2 ln 3, so

3 ln[(3)^2] - 6ln (3) = 0

That leaves you with pi (6 - 4) = 2 pi

- Calculus -
**Lin**, Sunday, March 30, 2008 at 10:50pmI'm confused. When I wrote it out by hand, I got:

ð(3ln(9)-6ln(3)+6)-(ln(1)-2ln(1)+2)

ð(ln(93)-ln(36)+6)- 2 (since ln(1)=0)

ð(ln(729)-ln(729)+6)-2

6ð-2

- Calculus -
**Lin**, Sunday, March 30, 2008 at 10:50pmthe weird symbol is pi

- Calculus -
- Calculus -
**Lin**, Sunday, March 30, 2008 at 10:51pmand that 93 is 9^3

- Calculus -
**Lin**, Sunday, March 30, 2008 at 10:52pmand that 36 is 3^6

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