Calculus
posted by Lin on .
Can someone solve this integral for me? My calculator just gives me a decimal approximation but I need an exact number. Thanks! :)
pi[{3ln(3)^2  6ln (3) + 6}  {ln(1)^2  2 ln(1) + 2}]

That does not look like a function to be integrated. It looks like a number to be calculated. You can start out simplifying it by recognizing that
ln(1) = 0.
When you write ln(3)^2, do you mean
[ln(3)]^2 or ln[3^2]? They are not the same. I will assume the latter.
ln [3^2] = 2 ln 3, so
3 ln[(3)^2]  6ln (3) = 0
That leaves you with pi (6  4) = 2 pi 
I'm confused. When I wrote it out by hand, I got:
ð(3ln(9)6ln(3)+6)(ln(1)2ln(1)+2)
ð(ln(93)ln(36)+6) 2 (since ln(1)=0)
ð(ln(729)ln(729)+6)2
6ð2 
the weird symbol is pi

and that 93 is 9^3

and that 36 is 3^6