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April 18, 2014

Homework Help: Chem

Posted by Ginger on Sunday, March 30, 2008 at 6:46pm.

How many minutes will it take a current of 66.049 Ampères to deposit 86.825 grams of aluminum (26.981538 g/mol)?

Al has a charge of 3, so n=3.
MM=26.981538g/mol

1eq=molarmass/charge
so 26.981538/3=8.9938
1eq=8.9938
1F=96485c/eq
F=13138.29477

Am I on the right path? I don't know where to go from here...

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