posted by Ginger on .
For the reaction,
3C2H2(g) ===> C6H6 at 25°C,
the standard enthalpy change is -631 kJ and the standard entropy change is -430 J/K, Calculate the standard free energy change (in kJ) at 25°C.
What is the formula that relates stand. entropy, enthalpy and free energy changes?
delta G = delta H - TdeltaS .
Post your work if you need additional assistance.
Delta G= -631000J - (298.15)(-430J)
Did I do this right?
That looks ok to me. You may want to check the number of significant figures.
3C2H2 --> C6H6