Homework Help: Chem

Posted by Ginger on Sunday, March 30, 2008 at 6:10pm.

For the reaction,
3C2H2(g) ===> C6H6 at 25°C,
the standard enthalpy change is -631 kJ and the standard entropy change is -430 J/K, Calculate the standard free energy change (in kJ) at 25°C.

What is the formula that relates stand. entropy, enthalpy and free energy changes?

Chem - DrBob222, Sunday, March 30, 2008 at 6:13pm
delta G = delta H - TdeltaS .
Post your work if you need additional assistance.
Chem - Ginger, Sunday, March 30, 2008 at 6:19pm
Delta G= -631000J - (298.15)(-430J)
= -502795J
=-502.7955KJ

Did I do this right?
Chem - DrBob222, Sunday, March 30, 2008 at 6:35pm
That looks ok to me. You may want to check the number of significant figures.

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