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Chem

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For the reaction,
3C2H2(g) ===> C6H6 at 25°C,
the standard enthalpy change is -631 kJ and the standard entropy change is -430 J/K, Calculate the standard free energy change (in kJ) at 25°C.

What is the formula that relates stand. entropy, enthalpy and free energy changes?

  • Chem -

    delta G = delta H - TdeltaS .
    Post your work if you need additional assistance.

  • Chem -

    Delta G= -631000J - (298.15)(-430J)
    = -502795J
    =-502.7955KJ

    Did I do this right?

  • Chem -

    That looks ok to me. You may want to check the number of significant figures.

  • Chem -

    3C2H2 --> C6H6

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