Posted by Anonymous on Sunday, March 30, 2008 at 4:26pm.
When standing 1.25 m in front of an amusement park mirror, you notice that your image is three times taller. What is the radius of curvature of the mirror?

Physics  Mirrors & Lenses  drwls, Sunday, March 30, 2008 at 4:53pm
I will assume it is an upright image, behind the mirror. The distance to the image is di = 3 do because of the 3x magnification, and do = 1.25 m. The minus sign is necessary for upright virtual images.
The focal length f is given by the equation
1/do + 1/di = 1/f
1/1.25 1/3.75 = 2/3.75 = 1/f
Therefore f = 1.87 m.
The radius of curvature is 2f, or 3.75 m. It is a concave mirror; otherwise f would be negative.
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