Posted by **Devon** on Sunday, March 30, 2008 at 3:35pm.

A ship travels 200km west from port and then 240km due south before it is disabled. Illustrate this in a vector diagram. Usa trigonometry to find the course that a rescue ship must take from port in order to reach the disabled ship.

i dont know where to begin, could someone just help know where to start?

- pre-calc -
**drwls**, Sunday, March 30, 2008 at 4:45pm
Draw an x-y graph with the port at the origin (x=0, y=0) Let up (+y) be north and right (+x) be east. After going west the ship is at (-200, 0), which means x=-200, y=0. Draw the line that it travelled as an arrow from the origin to that point. Then draw another arrow for the next part of its journey, from (-200,0) to (-200,-240)..The course that a rescue ship must take is from (0,0) to (-200,-240)

## Answer This Question

## Related Questions

- mathematics - a ship which started at port p, sailed 15 km due south to port q...
- Math - "A ship leaves port on a bearing of 34.0 degrees and travels 10.4 mi. ...
- Dyanamics - Two ships A&B leave port at same time the ship A is north-west at ...
- physics - A ship leaves its home port expecting to travel to a port 500.0 km due...
- Trigonometry - If a ship leaves port at 9:00 a.m. and sails due south for 3 ...
- calculus - At noon, Ship A is 100 km west of ship B. Ship A travels south at 35 ...
- geometry - A ship leaves port and heads due east at a rate of 32 miles per hour...
- Trigonometry - Navigation A ship leaves port at noon and has a bearing of S 29° ...
- phyics - A crippled ship is being assisted to port. The motor is stuck, and is ...
- physics - A viking sails from his home port and travels east at 15km/hr.after 10...

More Related Questions