Posted by Chris Adison on .
A 500 turn solenoid with a length of 20 cm and a radius of 1.5 cm carries a current of 2.0 A. A second coil of four turns is wrapped tightly about this solenoid so that it can be considered to have the same radius as the solenoid. Find the following when the current in the solenoid increases to 5.0 A in a period of 0.90 s.
(a) the change in the magnetic flux through the coil
T·m2
(b) the magnitude of the average induced emf in the coil
V

physics induced voltage 
bobpursley,
a. B=mu*N*i
dB/dt=mu*N*di/dt
b. apply Faraday's equation 
physics induced voltage 
Chris Adison,
So i use B=mu*N*i to find a than what does dB/dt=mu*N*di/dt mean?