Sunday

April 19, 2015

April 19, 2015

Posted by **daria** on Sunday, March 30, 2008 at 1:40am.

Show that y=loge(logex) is a solution of the equation

xd^2y/dx^2 + x(dy/dx)^2 + dy/dx=o

- calculus -
**drwls**, Sunday, March 30, 2008 at 3:07amThe first derivative of ln (ln x) is dy/dx = 1/(x*ln x)

The second derivative is:

d^2y/dx^2 = [-ln x/x^2 - (1/x^2)]/(ln x)^2

= -1/(x^2 ln x) -1/(x ln x)^2

x d^2y/dx^2 = -1/(x ln x) - (1/x)/lnx^2

It seems to fit the differential equation

Math/Trig - Which logarithmic equation is equivalent to L^m = E 1) LogL E = m 2...

equations of tangents and normals - hi, i'd really appreciate some help solving ...

calculus - hi, just wondering on how i should approach differentiating: loge1/(3...

calculus - Please help with this. I need the first derivative of f(x)=4(x+...

Calculus - Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x ...

CALCULUS HELP - Find the second derivative for the function 5x^3+60x^2-36x-41 ...

Calculus - Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x ...

Calculus - Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x ...

Calculus - Graph the curve and find its exact length. x = e^t + e^-t, y = 5 - 2t...

calculus - Please help with this. I submitted it below and was asked to clarify ...