Posted by **daria** on Sunday, March 30, 2008 at 1:36am.

find the derivative of the function y=x^x

Hence fin the coordinates of the turning point of the funcion y-x^x. Give the values correct to two decimal places

- calculus -
**drwls**, Sunday, March 30, 2008 at 7:04am
The derivative of that function is

y ' = (ln x + 1)*x^x

I will provide a website with the derivation separately.

I don't know what you mean by the "turning point of the function y-x^x". That function would always be zero. Do you mean the minimum of the function y = x^x?

- calculus -
**drwls**, Sunday, March 30, 2008 at 7:05am
See this website for how to differentiate the function:

http://www.analyzemath.com/calculus/Differentiation/first_derivative.html

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