Posted by daria on Sunday, March 30, 2008 at 1:36am.
find the derivative of the function y=x^x
Hence fin the coordinates of the turning point of the funcion yx^x. Give the values correct to two decimal places

calculus  drwls, Sunday, March 30, 2008 at 7:04am
The derivative of that function is
y ' = (ln x + 1)*x^x
I will provide a website with the derivation separately.
I don't know what you mean by the "turning point of the function yx^x". That function would always be zero. Do you mean the minimum of the function y = x^x?

calculus  drwls, Sunday, March 30, 2008 at 7:05am
See this website for how to differentiate the function:
http://www.analyzemath.com/calculus/Differentiation/first_derivative.html
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