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October 20, 2014

October 20, 2014

Posted by **Anonymous** on Sunday, March 30, 2008 at 1:18am.

- physics -
**drwls**, Sunday, March 30, 2008 at 2:47amThe radius of curvature of the ornament is 6.0 cm and the focal length is half that, 3.0 cm. Because if is convex, the focal length is considered negative.

For the image position,

1/do + 1/di = 1/f = -1/3.0

Since there is a demagnification of 1/4, di = -do/4

I used a minus sign because the image will be virtual, behind the reflecting surface.

1/do + 1/di = 1/do -4/do = -1/3

-3/do = -1/3

do = 9 cm.

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