Algebra II
posted by Lucy on .
Log6(6^9)=???
Answer: 9
Ine^3x=???
Answer: 3x
Use log5(2) = 0.4307 and log5(3) = 0.6826 to approximate the value of log5(12)
Answer:
log5(2) + log5(3)=log5(2^2*3)
2(0.4307) + 0.6826=1.544
so approximate value of log5(12)=1.544
I appreciate your checking my work.

Log6(6^9)=???
9 log6(6) = 9*1
Answer: 9 Right
Ine^3x=???
Answer: 3x Right
Use log5(2) = 0.4307 and log5(3) = 0.6826 to approximate the value of log5(12)
Answer:
log5(***4***) + log5(3)=log5(2^2*3)
2(0.4307) + 0.6826=1.544
Right method,, did not check arithmetic
so approximate value of log5(12)=1.544