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March 3, 2015

March 3, 2015

Posted by **Lucy** on Saturday, March 29, 2008 at 6:45pm.

Answer: 9

Ine^-3x=???

Answer: -3x

Use log5(2) = 0.4307 and log5(3) = 0.6826 to approximate the value of log5(12)

Answer:

log5(2) + log5(3)=log5(2^2*3)

2(0.4307) + 0.6826=1.544

so approximate value of log5(12)=1.544

I appreciate your checking my work.

- Algebra II -
**Damon**, Saturday, March 29, 2008 at 7:00pmLog6(6^9)=???

9 log6(6) = 9*1

Answer: 9 Right

Ine^-3x=???

Answer: -3x Right

Use log5(2) = 0.4307 and log5(3) = 0.6826 to approximate the value of log5(12)

Answer:

log5(***4***) + log5(3)=log5(2^2*3)

2(0.4307) + 0.6826=1.544

Right method,, did not check arithmetic

so approximate value of log5(12)=1.544

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